- #1
tommy2st
- 15
- 0
Find Devivaties with respect to x:
1). y=sin(cos(x+3));
2). tan(x+y)=ln x+ 5y.
heres my work...just need a double check
1). y=sin(cos(x+3));
2). tan(x+y)=ln x+ 5y.
1:y = sin(cos(x+3))
y' = cos(cos(x+3))(-sin(x+3))(1)
y' = {-sin(x+3)}{cos(cos(x+3))}
2. Tan(x+y) = lnx+5y
Sec^2(x+y)(1+y') = 1/x + 5yy'
y' = {((1/x))-(Sec^2(x+y))}/(Sec^2(x+y) - 5y)
1). y=sin(cos(x+3));
2). tan(x+y)=ln x+ 5y.
heres my work...just need a double check
1). y=sin(cos(x+3));
2). tan(x+y)=ln x+ 5y.
1:y = sin(cos(x+3))
y' = cos(cos(x+3))(-sin(x+3))(1)
y' = {-sin(x+3)}{cos(cos(x+3))}
2. Tan(x+y) = lnx+5y
Sec^2(x+y)(1+y') = 1/x + 5yy'
y' = {((1/x))-(Sec^2(x+y))}/(Sec^2(x+y) - 5y)