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1). y=sin(cos(x+3));

2). tan(x+y)=ln x+ 5y.

heres my work...just need a double check

1). y=sin(cos(x+3));

2). tan(x+y)=ln x+ 5y.

1:y = sin(cos(x+3))

y' = cos(cos(x+3))(-sin(x+3))(1)

y' = {-sin(x+3)}{cos(cos(x+3))}

2. Tan(x+y) = lnx+5y

Sec^2(x+y)(1+y') = 1/x + 5yy'

y' = {((1/x))-(Sec^2(x+y))}/(Sec^2(x+y) - 5y)