1. The problem statement, all variables and given/known data A proton moves with a speed of 4300 m/s in a direction 76.0° above positive x axis. It enters a region where a magnetic filed of 25x10^-6 Tesla exists in the positive x direction. Find the radius of the helix formed by the protons path and the distance between adjacent turns of helix. To find the distance, I'm not sure. I know I need to find distance around and time it takes for a complete circle. 2. Relevant equations Force of mag. field = qvsin∅B F=qvsin∅B=ma F= qvsin∅B = mv^2/r r = mvsin∅/ qB v = 2∏r/t t = 2∏r/v xf=xi + vt vyfinal = vyinitial + at 3. The attempt at a solution r = (1.67*10^-27 * 4300sin76°) / (1.602*10^-19 * 25*10^-6) r = 1.74m t = 2∏r/v t = .002542s so, vyfinal = vyinitial + at xf = 0 + 4300m/s(.002542m) xf = 10.9, which is NOT the answer.