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How do you find the domain of functions algebraically?
ex (3x-1)/(x+3)(x-1)
ex (3x-1)/(x+3)(x-1)
The domain of the function (3x-1)/((x+3)(x-1)) is defined as all real numbers except for x = -3 and x = 1, which are the values that cause division by zero. This conclusion is reached by identifying the points where the denominator equals zero, thus rendering the function undefined. The algebraic method for determining the domain involves solving for the values that make the denominator zero and excluding them from the domain.
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