Calculating Electric Force on q3 in Meters: A Superposition Approach

[veevee]

(x,y) axis in meters

q1=60microC (0,1)
q2=-34microC (2,0)
q3=13microC (2,2)

Fx3=? Fy3=?

i used superposition
F(net on 3)=F13+F23

broke it down into x and y components
Fx=(kq1q3/r13^2)(x/r13)
Fy=(kq1q3/r13^2)(y/r13) - (kq2q3/r23^2)

plugging in the numbers i got
Fx=1.3
Fy=-0.4

mastering physics says its wrong, and I can't seem to figure out where I went wrong...any suggestions?

 

[SammyS]

What did you use for r₁₃, r₂₃, x, and y ?

Be careful regarding the direction of the forces.

 

[veevee]

r13=sqrt(x²+y²)=sqrt(4+1)=2.2m

r23=2m

x=2
y=1

 

[SammyS]

It might be simply too much round-off error.

(sqrt(5))² = 5

2.2² = 4.84

 

[veevee]

the problem was i was entering 1 sig fig not 2 for F_y lol...online homework submissions...they'll waste your time for the simplest reasons..thanks though )