Find Final Kinetic Energy of a particle subject to two forces

Click For Summary
SUMMARY

The discussion focuses on calculating the final kinetic energy of a particle influenced by two forces. The user initially struggled with the equations needed to transition from the coordinates (0,0,0) to (1,0,0) and then from (1,0,0) to (1,1,0). The confusion centered around determining the work done by non-conservative forces (Wnc), but the user ultimately resolved their issue independently.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with kinetic energy equations
  • Knowledge of work-energy principles
  • Basic vector mathematics for coordinate transformations
NEXT STEPS
  • Study the work-energy theorem in classical mechanics
  • Learn how to calculate work done by non-conservative forces
  • Explore vector decomposition in physics
  • Review examples of kinetic energy calculations in multi-dimensional motion
USEFUL FOR

Students and professionals in physics, particularly those studying mechanics, as well as educators looking for practical examples of kinetic energy calculations involving multiple forces.

maguss182
Messages
16
Reaction score
0
Homework Statement
The force of gravity (-mg) in the k direction and the non conservative force (-b)i-(b)j-(b)k act on a particle that starts off at speed V(int) from the origin to a point (1,1,0), while moving first in the x direction than in the y direction. Find the final kinetic energy of the particle.
Relevant Equations
DeltaT-DeltaU=Wnc T=1/2mv^2 U=-mg,
I'm having trouble putting the rest of the equations together, I believe I need the different from (0,0,0) to (1,0,0) and then (1,0,0) to (1,1,0) right? Then solve for x direction and y direction. What would I use for Wnc tho? I'm very confused.
 
Physics news on Phys.org
nm i got it
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
6
Views
2K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
9
Views
1K
Replies
2
Views
1K
Replies
7
Views
2K
  • · Replies 56 ·
2
Replies
56
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
3K