Find Fmax for a 450g Particle Moving Along the x-Axis | Ex11.15

[ChrisMC]

A 450 g particle moving along the x-axis experiences the force shown in Figure Ex11.15. The particle goes from vx = 4.0 m/s at x = 0 m to vx = 7.5 m/s at x = 2 m. What is Fmax?

Where the maximum peak on the force by distance graph is at 1m

F=ma
v=d/t
a=v/t


I have no idea how to answer this. I tried to find the acceleration then multiply it by the mass

i got 7.2 n which was wrong

 

[ChrisMC]

http://www.webassign.net/knight/ex11-15.gif

 

[kuruman]

Use the work energy theorem
ΔKE = W_Net
You can calculate the change in kinetic energy using the given numbers. Since only F is acting on the particle, F is the net force. The work done by F is the area under the curve, so ...

 

[ChrisMC]

.5mv^2-.5mv^2 using 7.5 and 4 as the velocities. thank you very much

9.05625 btw