Two block problems with friction

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Homework Help Overview

The discussion revolves around a problem involving two blocks with friction, where a 20 kg block is placed on a 10 kg block. The coefficient of static friction is given, and a force is applied to the top block. Participants are exploring the implications of friction in this scenario and questioning the assumptions regarding its behavior.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the maximum frictional force and its implications on the motion of the blocks. There are questions about the necessity of forming equations based on the assumption of self-adjusting friction and the physical feasibility of the results obtained. Some participants express confusion about the conditions under which friction operates and the outcomes of their calculations.

Discussion Status

The discussion is ongoing, with participants raising various interpretations of the frictional forces at play. Some have suggested that the only physically viable options are either both blocks accelerating together or the top block sliding over the bottom block. There is a recognition of the need for clarity regarding the behavior of friction in this context, but no consensus has been reached.

Contextual Notes

Participants are grappling with the concept of static friction and its self-adjusting nature, questioning how it applies when the applied force exceeds certain limits. There is also mention of the role of the coefficient of friction and its constancy in relation to the surfaces involved.

Hamiltonian
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Homework Statement
A block of mass 20kg is placed on another block of 10kg the coefficient of static friction between the two surfaces = 0.3
the surface of contact between the 10kg block and floor is smooth. A force of 30N acts on the 20kg block. comment on the motion of the system
Relevant Equations
F = ma
the maximum value of friction between the surfaces of the blocks is ##60N##
the friction should be self-adjusting until this maximum value. Hence the force of friction in the given scenario should be = 30N but this is physically impossible as if this is the case the top block will be at rest and the bottom block will move.
hence I made the equations $$30 - f = 20a $$ $$10a = f$$

from this I got ##f = 10N##
but I don't understand why we are supposed to form these two equations are we supposed to do this out of necessity as we cannot say friction will be self-adjusting in the given scenario as it will lead to a physically impossible situation?
I don't as such have an issue with the question rather I don't understand why the above equations yield a correct answer as here friction is not-self adjusting.
 
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Hamiltonian299792458 said:
Homework Statement:: A block of mass 20kg is placed on another block of 10kg the coefficient of static friction between the two surfaces = 0.3
the surface of contact between the 10kg block and floor is smooth. A force of 30N acts on the 20kg block. comment on the motion of the system
Relevant Equations:: F = ma

the maximum value of friction between the surfaces of the blocks is ##60N##
the friction should be self-adjusting until this maximum value. Hence the force of friction in the given scenario should be = 30N but this is physically impossible as if this is the case the top block will be at rest and the bottom block will move.
hence I made the equations $$30 - f = 20a $$ $$10a = f$$

from this I got ##f = 10N##
but I don't understand why we are supposed to form these two equations are we supposed to do this out of necessity as we cannot say friction will be self-adjusting in the given scenario as it will lead to a physically impossible situation?
I don't as such have an issue with the question rather I don't understand why the above equations yield a correct answer as here friction is not-self adjusting.
The answer you found is the only answer that makes physical sense. There are only two physically viable options:

a) Both block accelerate together. This requires sufficient friction between the blocks.

b) The top block has a greater acceleration and slides across the bottom block. This requires insufficient friction for option a).
 
PeroK said:
The answer you found is the only answer that makes physical sense. There are only two physically viable options:

a) Both block accelerate together.

b) The top block has a greater acceleration and slides across the bottom block.
are we supposed to do this out of necessity as we cannot say friction will be self-adjusting in the given scenario as it will lead to a physically impossible situation?
 
Hamiltonian299792458 said:
are we supposed to do this out of necessity as we cannot say friction will be self-adjusting in the given scenario as it will lead to a physically impossible situation?
I can't make any sense of that. Something has to happen!

If you don't like the physical solution you found, then propose another one.
 
Consider this, it is the force of friction that is responsible for the acceleration of the 10 Kg block. That force is constant as the 20 Kg block slides across it. What do you expect if the force on the 20 Kg block is increased or the coefficient of friction is decreased?
 
gleem said:
Consider this, it is the force of friction that is responsible for the acceleration of the 10 Kg block. That force is constant as the 20 Kg block slides across it. What do you expect if the force on the 20 Kg block is increased or the coefficient of friction is decreased?
it is indeed the force of friction that is responsible for the acceleration of the 10kg block.
the coefficient of friction has to be constant for a pair of surfaces!

p.s. I am having difficulty explaining my question (which I know is a bad sign) hence I think it would be best not to spend more time on this if I am able to rephrase my question in a better way I will post it.
 
Hamiltonian299792458 said:
the friction should be self-adjusting until this maximum value. Hence the force of friction in the given scenario should be = 30N
Self-adjusting, yes, but to what criterion? Friction relates to relative tangential motion of the surfaces in contact. In static friction, the force adjusts, if it can, to ensure no relative motion. There is no reason to suppose that requires 30N.
 
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