MHB Find force with Young's modulus

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SUMMARY

The discussion focuses on calculating the force applied by a piano tuner to stretch a steel piano wire using Young's modulus. The original length of the wire is 1.35 m, with a diameter of 0.850 mm, and the wire is stretched by 8.50 mm. Young's modulus for steel is given as 20.0 × 1010 Pa. The formula used for the calculation is F = (E × π × r2 × ΔL) / L, where ΔL represents the change in length and L is the original length.

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cbarker1
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Q: Calculate the force (in N) a piano tuner applies to stretch a steel piano wire 8.50 mm, if the wire is originally 0.850 mm in diameter and 1.35 m long. (Young's modulus for steel is 20.0 1010 Pa.)

Work F=Y*A*change in L/L_0

I have no idea what is L_0 and L_f? Please help me.
 
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$L = 1.35 \, m$

$\Delta L = 8.5 \times 10^{-3} \, m$

$r = 4.25 \times 10^{-4} \, m$

$E=2.0 \times 10^{11} \, N/m^2$$F = \dfrac{E \cdot \pi r^2 \cdot \Delta L}{L}$

ymod.gif
 

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