Calculating Force on a Stretched Steel Rod | Young's Modulus 200*109 Pa

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SUMMARY

The discussion focuses on calculating the force exerted on a cylindrical steel rod using Young's Modulus, which is 200 x 109 Pa. The rod has an original length of 250 cm and a diameter of 0.254 cm, resulting in a calculated force of 3400 N after accounting for a stretch of 0.85 cm. The equation used is F/A = Y(ΔL/L0), where the user struggled with determining the cross-sectional area of the rod. Accurate area calculation is crucial for obtaining the correct force value.

PREREQUISITES
  • Understanding of Young's Modulus and its application in material science.
  • Knowledge of basic geometry to calculate the cross-sectional area of a cylinder.
  • Familiarity with the formula F/A = Y(ΔL/L0) for stress and strain calculations.
  • Basic algebra skills for manipulating equations and solving for unknowns.
NEXT STEPS
  • Learn how to calculate the cross-sectional area of a cylinder using the formula A = π(d/2)2.
  • Study the principles of stress and strain in materials to deepen understanding of Young's Modulus.
  • Explore practical applications of Young's Modulus in engineering and materials science.
  • Investigate common errors in force calculations involving elastic materials and how to avoid them.
USEFUL FOR

This discussion is beneficial for engineering students, material scientists, and professionals involved in mechanical design and analysis, particularly those working with tensile properties of materials like steel.

fightboy
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A cylindrical steel rod is originally 250 cm long and has a diameter of 0.254 cm. A force is applied longitudinally and the rod stretches 0.85 cm. What is the magnitude of the force? The value for Young's Modulus for steel is 200*109 Pa.
The correct answer is 3400 N, i used the equation F/A=Y(ΔL/L0) but kept getting some weird numbers. I think I'm screwing up on finding the area, since in most of the problems the area is already given. Can someone help me figure this out?
 
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fightboy said:
A cylindrical steel rod is originally 250 cm long and has a diameter of 0.254 cm. A force is applied longitudinally and the rod stretches 0.85 cm. What is the magnitude of the force? The value for Young's Modulus for steel is 200*109 Pa.
The correct answer is 3400 N, i used the equation F/A=Y(ΔL/L0) but kept getting some weird numbers. I think I'm screwing up on finding the area, since in most of the problems the area is already given. Can someone help me figure this out?

Things will go much easier if you post your calculations, so says the Magic 8-Ball. :smile:
 

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