Find i such that ##t_{net}=0## for a loop/(Cross prod. help)

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Homework Help Overview

The problem involves a wood cylinder with wire wrapped around it, released on an inclined plane in a uniform magnetic field. The goal is to determine the least current needed to prevent the cylinder from rolling down the incline, focusing on the balance of torques.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between torque and the forces acting on the cylinder, questioning the direction of the torques and the appropriate axes for analysis. There is confusion regarding the use of net torque versus net forces in the context of the problem.

Discussion Status

Participants are exploring the implications of setting the net torque to zero and questioning whether this is sufficient to prevent rolling. Some have provided insights into the axes of rotation and the conditions necessary for equilibrium.

Contextual Notes

There is an ongoing discussion about the definitions of axes and planes in relation to the cylinder's motion, as well as the assumptions made about the forces and torques involved.

Potatochip911
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Homework Statement


A wood cylinder of mass ##m## and length ##L## with ##N## turns of wire wrapped around it longitudinally, so that the plane of the wire coil contains the long central axis of the cylinder. The cylinder is released on a plane inclined at an angle ##\theta## to the horizontal, with the plane of the coil parallel to the incline plane. If there is a vertical uniform magnetic field ##B##, what is the least current ##i## through the coil that keeps the cylinder from rolling down the plane?

woodcylinder.jpg


Homework Equations


##\vec{\tau}=\vec{\mu}\times \vec{B}##
##\vec{\tau}=\vec{r}\times \vec{F}##

The Attempt at a Solution



Since the cylinder isn't rolling down the plane we have that ##\tau_{net}=0##, the torque from coil on the cylinder is ##\tau_{coil}=\vec{\mu}\times\vec{B}=NiAB\sin\theta## and the torque from the cylinder's weight is ##\tau_{w}=\vec{r}\times\vec{F}=rmg\sin\theta##, now setting these equal to each other solves the problem but I'm confused about the direction of these forces from the right hand rule/cross product. I'll draw a picture to show you:
ngqdcz.png


Which makes no sense and I also can't get the torque from the cylinders weight to go in the correct direction, if someone could show/tell me what's wrong with my vector diagram that would be great.
 
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Potatochip911 said:
Which makes no sense and I also can't get the torque from the cylinders weight to go in the correct direction, if someone could show/tell me what's wrong with my vector diagram that would be great.
Why do you think it does not make sense?
Please show your working with regard to the torque from gravity.
 
haruspex said:
Why do you think it does not make sense?
Please show your working with regard to the torque from gravity.
I messed up the first cross product, it should be ##\vec{u}\times\vec{B}=\hat{j}##, and for torque from gravity:
2hwmnpl.png

I will explain why this doesn't make sense to me. The question is asking what the smallest value of current is that will stop the cylinder from rolling down the plane. I just can't see how setting the net torque equal to zero in the y plane will hold the cylinder in place.

I would think that for the cylinder we would need ##F_{netx}=0## and ##F_{nety}=0## not ##\tau_{net}=0##
 
Potatochip911 said:
I just can't see how setting the net torque equal to zero in the y plane will hold the cylinder in place.
There isn't a y plane, there's a y axis. If it were to roll, which axis would it rotate about?
 
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haruspex said:
There isn't a y plane, there's a y axis. If it were to roll, which axis would it rotate about?
I suppose it would roll about the y axis
 
Potatochip911 said:
I suppose it would roll about the y axis
Right. So if the torques about the y-axis balance, it won't roll.
 

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