Find Initial Velocity given angle, distance, height launched from.

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SUMMARY

The discussion focuses on calculating the initial velocity of a nerf gun fired from a height of 0.98 meters at an angle of 15 degrees, covering a horizontal distance of 7.86 meters. The relevant equations include the kinematic equations for projectile motion, specifically x=xo+vot and y=yo+vot+.5gt². The user successfully derived the time of flight equation and suggested substituting the vertical component of velocity to solve for the unknowns. The final solution involves using two equations with two unknowns to determine the initial velocity and its components.

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1. A nerf gun in a vacuum is fired from .98 meters at an angle of 15degrees, going 7.86m. Find the initial velocity of the gun, then find the horizontal and vertical components of the initial velocity.

Knowns
g=-9.8m/s2
yo
=.98m
xo=0m
y=o ( the final height of the dart is 0)
x=7.86m
θ=11 degrees



Homework Equations


x=xo+vot
y=yo+vot+.5gt2
vox=vocosθ
voy=vosinθ

The Attempt at a Solution


So first i simplified the x equation down to get time on one side to get
(x-xo)/(vocos11)=t
Then i plugged in the numbers to get
{7.86/(vocos11)}=t

Then i plugged in the parts for the y equation,
-.98=voyt+-4.9t2
Now what do i do? do take out a t and plug in the x equation?
 
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Why not substitute in v_0* sin (theta) = v_0y. Then you have two equations and two unknowns and from that everything else is easy to find!
 

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