The problem involves calculating the integer part of A, defined by the equation A=(16×72+17×73+18×74+19×75)/(16×71+17×72+18×73+19×74) multiplied by 150. The solution reveals that A can be expressed as 152 plus a fraction involving weighted sums of integers. The numerator of the fraction is 16×8 + 17×6 + 18×4 + 19×2, while the denominator consists of the same weights applied to the integers 71, 72, 73, and 74. This approach simplifies the calculation and highlights the cleverness of the solution. The integer part of A is thus determined to be 152.