Find Integral of sqrt(e^(9x)) - Incorrect Solution Explained

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SUMMARY

The integral of the function \(\sqrt{e^{9x}}\) is not simply \(\int(e^{9x/2}) dx\). The correct approach requires recognizing that \(\sqrt{e^{9x}} = e^{9x/2}\) and applying the integral formula correctly. The correct integral is \(\frac{2}{9} e^{9x/2} + C\). This highlights the importance of verifying results by differentiation to ensure accuracy.

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Find the integral.
\int\sqrt{e^{9x}} dx

I figured that \int\sqrt{e^{9x}} dx is equal to \int(e^{9x/2}) dx so the integral should simply be e^{9x/2}+C

Why isn't this correct?
 
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Take the derivative of your answer and you'll see what you left out. Almost got it.
 
2/9! Thanks a ton.
 

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