- #1

intenzxboi

- 98

- 0

## Homework Statement

f(x)= x^3 + kx^2 + 19x

## The Attempt at a Solution

So what i did was take the derivative of f(x)

3x^2 + 2kx + 19

\sqrt{}

(3x+ [tex]\sqrt{19}[/tex]) (x+ [tex]\sqrt{19}[/tex])

so then i can assume that 3x[tex]\sqrt{19}[/tex] + x[tex]\sqrt{19}[/tex] = 2kx

and then k i got to be 2[tex]\sqrt{19}[/tex]

Im i right?? i feel like I'm completely lost..