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As shown in Figure Q1a, a frictionless, massless, piston, supported by two springs, A and B, is held by a pin in a vacuum inside a rigid-walled container. The properties of the springs are: spring constants kA = 3,859 and kB = 3,090 (in N/m), natural lengths LA0 = 0.03 and LB0 = 0.1 (in m). When the piston is pinned to the wall, the lengths of the springs are LA1 = 0.1 and LB1 = 0.1 (in m), respectively. Both springs possess dissipative properties so that after the pin is pulled, the piston eventually comes to rest at an equilibrium position. Find the length of spring A in this equilibrium position (LA2) in units of m.

Equations so far:

Models:

Elastic Energy Constituitive Relation: (E_{2}- E_{1}) = (k/2)(x_{2}^{2}- x_{1}^{2})

First Law of thermodynamics: (E_{2}- E_{1}) = (Q_{1-2}) - (W_{1-2})

Second Law of thermodynamics...

Don't really know where to start? Help appreciated

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# Find length of spring A in equilibrium position

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