Find Limit of Sequence: an = (1/(e^(4n)+n^2))^1/n

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The limit of the sequence defined by an = (1/(e^(4n)+n^2))^1/n converges to 1/e^4. To solve this, applying the binomial expansion to the denominator and utilizing L'Hôpital's rule for limit evaluation are effective strategies. The discussion confirms that these mathematical techniques lead to the correct conclusion regarding the limit of the sequence.

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Find the limit of the sequence whose terms are given by

an = ( [1/(e^(4n)+n^2)] )^1/n

I am not really sure how to approach this problem.

thanks!
 
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Try the binomial expansion of denominator and apply the limits to each term (don't forget that you always can use the L'Hopital rule for those limits). I guess the that the limit is 1/e^4.
 

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