Find Mass of Object 2 in Two-Mass Pulley System

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Homework Help Overview

The problem involves a two-mass pulley system where one mass (Object 1) accelerates upwards, and the task is to determine the mass of the second object (Object 2). The context is rooted in classical mechanics, specifically dealing with forces and motion in a system of connected masses.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss setting up equations based on net forces acting on each mass, with attempts to apply Newton's second law. Some participants express uncertainty about their calculations and the correct setup of equations.

Discussion Status

There is ongoing exploration of the problem, with participants providing feedback on each other's approaches. Some guidance has been offered regarding the need for free body diagrams and the correct summation of forces. Multiple interpretations of the problem setup are being considered.

Contextual Notes

Participants note potential issues with the equations used, including the presence of incorrect signs and the need for clarity on the forces acting on each mass. There is also mention of homework constraints that may affect the approach taken.

Fresh Coffee
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Homework Statement


Two masses are attached by a light string and looped over two frictionless pulleys. Object 1 (200g) accelerates upwards at a rate of 4.90 m/s squared. Determine mass of object 2.



Homework Equations

The Attempt at a Solution


I tries doing this but don't think its right.

Fnet= F1 + F2
ma= m1 + m2
-m2g = m1g – ma
m2g=ma-m1g
m2g= m(a-g)
m2g/g=m(a-g)/g
m2=m(a)
m2=(.2kg)(4.90m/s 2)
m2=.98 kg or 980 grams
 
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Fresh Coffee said:

Homework Statement


Two masses are attached by a light string and looped over two frictionless pulleys. Object 1 (200g) accelerates upwards at a rate of 4.90 m/s squared. Determine mass of object 2.



Homework Equations

The Attempt at a Solution


I tries doing this but don't think its right.

Fnet= F1 + F2
ma= m1 + m2
-m2g = m1g – ma
m2g=ma-m1g
m2g= m(a-g)
m2g/g=m(a-g)/g
m2=m(a)
m2=(.2kg)(4.90m/s 2)
m2=.98 kg or 980 grams

Yes, that solution is not correct. The problem has only two masses but your equation "-m2g = m1g – ma" has three different masses in it. you must fix that. Besides, there is also a sign mistake on your net force calculation. Make sure you draw a diagram before attempting to solve any problem like that. Include all the relevant forces in your diagram.

Also (a-g)/g is not equal to a. That's just basic algebra
 
You did not do this correctly.

Start by setting up two different equations by ∑F=ma for each mass.
 
Was anything right?
 
The units look right.
 
Lol ok thanks. I shall endeavour to solve this enigmatic question.
 
Ok so would finding out the net force of object 1 help?
 
It's a start.
 
Ok so I have set up two equations for each mass.

Fnet1=ma

Fnet2=ma

Fnet1=(.2kg)(4.90m/s squared)

Fnet1=.98 N

However I am stumped what to do with Fnet2. I go Fnet2=m(-4.90 m/s squared) then ma=m(-4.90m/s squared) but don't know what to do next.
 
  • #10
Did you do a free body diagram of each mass? Include all the forces acting on each mass. These will add up to Fnet for each case.
 
  • #11
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
 
  • #12
I can't get it. I'v tried all sorts of ways but its that darn net force that I can't get! If I could just get that I'd have it.
 
  • #13
Fresh Coffee said:
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
Are the gravity forces acting on object 1 and 2 the same? If not, then don't call them both Fg. What about Ft? Is that the same for both objects?
 
  • #14
Fresh Coffee said:
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
Great, now sum them up to get Fnet.
 
  • #15
mass of object 2 = 600 grams
 
  • #16
Yeah, that's good to know. But sum up all the forces you outlined above in an equation and set it equal to Fnet.
 
  • #17
I don't need to. All I need is mass of object 2.
 
  • #18
that's not correct. You have to sum up all the forces and set it to ma.
 
  • #19
ScreenShot2014-03-27at32025PM_zpsb9fe484f.jpg
 
  • #20
There is a minus sign missing in lines 1 through 3. Everything else seems correct. You should wait until the very last step before plugging in any values such as the m1 and g. Algebra is easier than arithmetic.
 

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