Find mass of steam using the 'Ideal Gas Equation'.

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SUMMARY

The mass of steam above water at 122 degrees Celsius can be calculated using the Ideal Gas Equation, pV = nRT. Given the volume of steam as 4.2 x 10^-3 m³ and the pressure as 2.1 x 10^-5 Pa, the molar mass of water is 0.018 kg/mol, and the molar gas constant is 8.3 J/(mol·K), the correct mass of steam is determined to be 4.8 x 10^-3 kg. The conversion of temperature from Celsius to Kelvin is essential, resulting in 395 K. Proper unit conversion and application of the Ideal Gas Law are critical for accurate calculations.

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  • Understanding of the Ideal Gas Law (pV = nRT)
  • Knowledge of unit conversions (Celsius to Kelvin)
  • Familiarity with molar mass calculations
  • Basic algebra for solving equations
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  • Review the Ideal Gas Law applications in thermodynamics
  • Learn about unit conversions, specifically temperature and mass
  • Explore molar mass calculations and their significance in gas laws
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Lenstonbain
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Show that there is a mass of (4.8 x 10^-3)kg of steam above the water when the temperature is 122 celsius?

Volume of Steam = 4.2 x 10^-3 (metres cubed)

Pressure of steam= 2.1 x 10^-5 (Pa)

molar mass of water = 18g per mole

molar gas constant = 8.3 Joules/mol/K



Homework Equations



pV= nRT

The Attempt at a Solution



The mass of steam given in the question doesn not come out of this equation whenever I input the numbers and I do not know why. I have made sure I used the correct units, i.e. 122 celsius is 395 Kelvin, and 18g is 0.018 kg, but the answer still does not work out.

Could somebody please show me the working that gives the correct steam mass as given in the question.

Thanks in advance for any help
 
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Post your working on how you did the problem. Perhaps you just made an error in calculation, without posting what you did, we won't know whether or not you were on the right track.
 

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