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Lenstonbain
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Show that there is a mass of (4.8 x 10^-3)kg of steam above the water when the temperature is 122 Celcius?
Volume of Steam = 4.2 x 10^-3 (metres cubed)
Pressure of steam= 2.1 x 10^-5 (Pa)
molar mass of water = 18g per mole
molar gas constant = 8.3 Joules/mol/K
pV= nRT
The mass of steam given in the question doesn not come out of this equation whenever I input the numbers and I do not know why. I have made sure I used the correct units, i.e. 122 Celcius is 395 Kelvin, and 18g is 0.018 kg, but the answer still does not work out.
Could somebody please show me the working that gives the correct steam mass as given in the question.
Thanks in advance for any help
Volume of Steam = 4.2 x 10^-3 (metres cubed)
Pressure of steam= 2.1 x 10^-5 (Pa)
molar mass of water = 18g per mole
molar gas constant = 8.3 Joules/mol/K
Homework Equations
pV= nRT
The Attempt at a Solution
The mass of steam given in the question doesn not come out of this equation whenever I input the numbers and I do not know why. I have made sure I used the correct units, i.e. 122 Celcius is 395 Kelvin, and 18g is 0.018 kg, but the answer still does not work out.
Could somebody please show me the working that gives the correct steam mass as given in the question.
Thanks in advance for any help