Find maxima angle of two interfering waves

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joelkato1605
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Homework Statement
See attached file. (m=0,2,4,6,...)
Relevant Equations
dsin(theta)=m(lambda)
I drew a diagram in the attached files as well, but the the scenario seems to be the same as the double slit experiment, but I don't understand why the answer contains cos instead of sin.
 
Attachments
  • Text excerpt from a physics textbook: two coherent point sources separated by δ produce a circular fringe pattern on a distant screen, with maxima at θ = cos^-1(mλ/δ), equation (4.14).
    Capture.PNG
    26.4 KB · Views: 197
  • Hand-drawn diagram of two point sources emitting circular wavefronts, with a vertical screen on the right, a dashed arrow labelled delta, and a perpendicular line from one source to the ray path.
    Capture.PNG
    74.6 KB · Views: 199
  • Handwritten diagram of two-slit interference: two sources separated by d, a line from the midpoint to a distant screen at angle θ, and a path-difference triangle with dx. Below, sinθ = dx/d, d sinθ = dx = mλ, sinθ = mλ/d.
    Capture2.PNG
    52.1 KB · Views: 168
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Where are the sources in you sketches ?
And the line joining the sources ?
If the screen is normal to the line joining the sources, where is the screen ?
 
joelkato1605 said:
... I don't understand why the answer contains cos instead of sin.
Read the original question carefully. You should see that θ is the angle with respect to the line joining the sources, so the angle you've marked as θ is in fact 90º – θ.

(It's more conventional to define θ in the way you interpreted it, but they've done it differently in this question.)
 
Steve4Physics said:
Read the original question carefully. You should see that θ is the angle with respect to the line joining the sources, so the angle you've marked as θ is in fact 90º – θ.

(It's more conventional to define θ in the way you interpreted it, but they've done it differently in this question.)
Oh! Thanks so much I completely missed that.
 
And did you find a
circular interference fringe pattern
on this screen ? Can you make that explicit ?