Find Min Force to Keep 50kg Block in Place

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SUMMARY

The minimum force required to keep a 50kg block of wood in place against a smooth wall, given a coefficient of static friction of 0.13, is determined by balancing the frictional force with the gravitational force acting on the block. The correct approach involves setting the frictional force equal to the weight of the block, leading to the equation Ff = Fg. The frictional force is calculated using the formula Ff = µFn, where Fn is the normal force applied by the wall.

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  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Familiarity with force equations: Fg = mg and Ff = µFn
  • Basic algebra for solving equations
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  • Study the relationship between normal force and frictional force in static scenarios
  • Explore examples of static friction problems in physics textbooks
  • Learn about the implications of different coefficients of friction on force calculations
  • Investigate real-world applications of static friction in engineering and design
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of static friction in action.

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Homework Statement


a 50kg block of wood is pressed against a smooth wall by a force perpendicular to the wall. if the coefficient of static function is .13, what is the minimum force that is necessary to keep the block of wood in place.

Homework Equations


Fg= mg
Fn = ma
Ff= µ Fn = µma
Fa = ma

The Attempt at a Solution


Ff+Fn-fa = 0 since we want the block to be still.
µma +ma = fa
.13*50kg*a + 50kg*a = fa
[(.13*50)+50]a=ma
56.5a= 50a
this is wrong.
 
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Actually, what you want is for the frictional force (which points upward, in this case) to be equal in magnitude to the weight of the block of wood (which points downward). So, your equation Ff+Fn-fa = 0 is not correct; it should be just Ff - Fg = 0. You then need to use the relationship between the normal force and the frictional force.

HTH,

jIyajbe
 

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