- #1

- 4

- 0

## Homework Statement

Scroll down for pic related

Determine the tension

in the cable P that will give the 50 kg block a steady accelerationof 2.0 m/s^2 up the incline.

## Homework Equations

Where am I going wrong?

## The Attempt at a Solution

Let Fa=force applied

I calculated the DeltaF to be 100N

(F=ma, F=50(2), F=100)

I calculated the force normal to be 424.8N

(Fn=50*9.81cos30)

I calculate Fg in x direction to be 245.25

(50*9.81sin30)

I calculated Fres to be (106.7-0.125Fa)

Fa is moving opposite from the fg, so I figured less force needs to be canceled out by the Fn. Will depend on force applied.

(Fn-Fasin30)(u), (426.8-0.5Fa(.25))

Since the acceleration in upwards on the plane, both the Fg(x) and Fres will be resistive forces. The Fa thus will have to overcome both of these forces added together.

Everything included:

Fa-Fres-Fg(x)+Facos(∅)=0

100-245.25- (106.7-0.125Fa)+Facos30=0

145.25+(106.7-0.125Fa)/Cos30)=Fa

And I tried subsituting the values of the multiple choice answers for Fa, but none of them worked out correctly.

Thanks in advance.