Find Net Electric Field Magnitude & Direction in an Equilateral Triangle

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Homework Help Overview

The discussion revolves around calculating the net electric field at the centroid of an equilateral triangle, focusing on both its magnitude and direction. Participants are exploring the appropriate equations and methods for this scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to identify the correct equation for calculating the net electric field, initially suggesting a formula related to force. Some participants clarify that a vector approach is necessary for electric fields. Questions are raised about how to determine the direction of the electric field, with mentions of using x and y components.

Discussion Status

The discussion is active, with participants providing guidance on the need for a vector approach and confirming the use of component breakdowns for direction. There is an ongoing exploration of the concepts involved, but no consensus has been reached yet.

Contextual Notes

Participants are navigating the complexities of vector addition in the context of electric fields, with some uncertainty about the initial assumptions regarding the equations to use.

kevykevy
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Find the magnitude and direction of the net electric field at the centre (or centroid) of the triangle.

The triangle is equilateral and the point of reference is in the middle of the triangle.

What I want to know is what equation do I use to figure this out?

At first I thought it was: Fnet = kq1q2/r^2

Is that right?, if not can you tell what to use?
 
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That's almost right...the question asks for the net electric field, which means you have to use a vector, not just the magnitude as you've shown.

[tex]\vec{E} = \frac{kq}{r^2}\hat{r}[/tex]
 
Also, how do I find the direction of the field?

Do I have to use some sort of x and y component breakdown?
 
kevykevy said:
Do I have to use some sort of x and y component breakdown?

That's right.
 

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