Find Order Notation of x√(1+x^2)

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The discussion focuses on the order notation of the expression x√(1+x²), demonstrating that it can be approximated as x + (1/2)x³, which is represented as O(x) near zero. This equivalence arises from the Taylor series expansion of the function at zero, utilizing the binomial series. The assertion that the series expansion is bounded by a constant multiple of x holds true only in the vicinity of zero, while at infinity, the expression behaves quadratically as √(1+x²) approaches |x|.

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Teacher has:

[tex]x\sqrt{1+x^2}=x+\frac{1}{2}x^3...(= O(x))[/tex]

in finding order notation of expression.

How is L.H.S. equal to R.H.S.?
 
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The first equation is an expansion of the function [tex]x\sqrt{1 + x^2}[/tex] in a Taylor series at zero, using the binomial series.

The second equation is a statement that the series expansion is bounded by a constant multiple of [tex]x[/tex]. This is true only near zero, not near infinity (near infinity, [tex]\sqrt{1 + x^2}[/tex] looks like [tex]|x|[/tex], so [tex]x\sqrt{1 + x^2}[/tex] grows quadratically). Near zero, the written-out version of the big-O notation is: there exist constants [tex]C > 0[/tex] and [tex]\delta > 0[/tex] so that, whenever [tex]|x| < \delta[/tex], [tex]|x\sqrt{1 + x^2}| < C|x|[/tex]. This statement is abbreviated [tex]x\sqrt{1 + x^2} = O(x) \textrm{ as } x \to 0[/tex].
 

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