- #1
Kernul
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Homework Statement
Does a linear transformation ##g : \mathbb{R}^2 \rightarrow \mathbb{R}^2## so that ##g((2, -3)) = (5, -4)## and ##g((-\frac{1}{2}, \frac{3}{4})) = (0, 2)## exist?
Homework Equations
The Attempt at a Solution
For a linear transformation to exist we need to know if those two satisfy the following conditions:
##g(\vec v_1 + \vec v_2) = g(\vec v_1) + g(\vec v_2)## for any ##\vec v_1, \vec v_2## in ##\mathbb{R}^2##
##g(\alpha \vec v) = \alpha g(\vec v)## for any scalar ##\alpha##
So I thought I should do like this:
I sum the two vectors ##(2, -3)## and ##(-\frac{1}{2}, \frac{3}{4})## like this ##g((2, -3) + (-\frac{1}{2}, \frac{3}{4}))## and put it equal to the sum of ##(5, -4)## and ##(0, 2)##. I will then have something like this:
##g((2, -3) + (-\frac{1}{2}, \frac{3}{4})) = (5, -4) + (0, 2)##
##g((\frac{3}{2}, -\frac{9}{4})) = (5, -2)##
But at this point I actually don't know if it really exist or not. Am I missing something?