Find phase angle of RLC network

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SUMMARY

The discussion focuses on calculating the phase angle in an RLC circuit using complex impedance. The user attempts to solve the problem using two methods: one involving direct voltage summation and the other applying Ohm's law with impedance. The correct approach emphasizes using the known current to determine the voltage drop across the inductor, represented as 0.5<90. The user expresses confusion over the methods and seeks clarification on the correct application of voltage and impedance addition.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with complex impedance notation
  • Knowledge of Ohm's law in AC circuits
  • Ability to manipulate phasors and phase angles
NEXT STEPS
  • Study the concept of complex impedance in RLC circuits
  • Learn how to apply Kirchhoff's voltage law in AC analysis
  • Explore the calculation of phase angles in AC circuits
  • Review the use of phasor diagrams for circuit analysis
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Electrical engineering students, circuit designers, and anyone involved in analyzing RLC networks and AC circuit behavior.

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Homework Statement


Please see attachment for circuit and parameters.

Homework Equations


i --> 90 phase angle for inductor so Z of inductor = 0.5<90
sum of voltages = 0
#<40 = #*cos(40) + i*sin(40)*#

The Attempt at a Solution


shteii01 - 100 + 0.5<90 + V2<theta = 0 --> 100 + 0.5*cos(90) + i*sin(90)0.5+V2*cos(theta)+i*sin(theta)*V2 = 0 --> two unknowns
OR
delta V = I * Z and then take V1 - delta V to find V2. The work seems simple but I get the wrong answer! Note that the answer I have in the attachment was my first solution which I did in my head - not the one I got from the methods shown above. Thanks for the help.
 

Attachments

  • Screen Shot 2015-02-12 at 6.49.54 PM.png
    Screen Shot 2015-02-12 at 6.49.54 PM.png
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I don't understand your first approach because you would appear to be adding voltages and impedances together in some way. But your second approach should work just fine. Since you are given the current you can find the potential drop across the inductor as you say. Can you show the details of that attempt?
 

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