Find Point of Intersection for Planes in 3D Space

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Homework Help Overview

The discussion revolves around finding the point of intersection of two lines in 3D space, defined by their parametric equations. Participants are also tasked with determining the plane that these lines define.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about how to find the intersection of the lines and recognize that this step is necessary to proceed with finding the plane. There are suggestions to equate the parametric equations to derive relationships between the parameters.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to solving for the parameters involved. Some guidance has been offered regarding using additional equations derived from the parametric forms to solve for the variables.

Contextual Notes

There is a noted lack of clarity on how to approach the intersection problem, and participants are working with the assumption that they need to find both a point and a normal vector to define the plane.

miglo
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Homework Statement


find the point of intersection of the lines x=2t+1, y=3t+2, z=4t+3 and x=s+2, y=2s+4, z=-4s-1
then find the plane determined by these lines


Homework Equations





The Attempt at a Solution


i have no idea how to find the point of intersection for those two lines
but i figured that I am going to need that in order to find the plane, since ill need a point and the normal vector to find the plane, and i can just find the normal vector by using the cross product on the two vectors that are parallel to the lines
but I am stuck on the very first part, how do i find the intersection?
 
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miglo said:

Homework Statement


find the point of intersection of the lines x=2t+1, y=3t+2, z=4t+3 and x=s+2, y=2s+4, z=-4s-1
then find the plane determined by these lines


Homework Equations





The Attempt at a Solution


i have no idea how to find the point of intersection for those two lines
but i figured that I am going to need that in order to find the plane, since ill need a point and the normal vector to find the plane, and i can just find the normal vector by using the cross product on the two vectors that are parallel to the lines
but I am stuck on the very first part, how do i find the intersection?

Since 2t+1=x and s+2=x you can say that 2t+1=s+2. Can you see what to do now?
 
solve for one of the variables?
 
miglo said:
solve for one of the variables?

Sure. You can use y and z to make two more equations. Solve them for t and s. You've got three equations in the two unknowns s and t.
 

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