The discussion focuses on solving the vector function r(t) given the second derivative r''(t) = 6i - 4cos(2t)j + 9e^(3t)k, along with initial conditions r'(0) = 4i + 3k and r(0) = j + k. The solution involves integrating the second derivative to find the first derivative r'(t) and subsequently r(t). The user emphasizes the need to integrate the components of r''(t) to derive the position vector r(t).
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If r(t) = x(t)i + y(t)j + z(t)k, then r''(t) = x''(t)i + y''(t)j + z''(t)k.mamma_mia66 said:Homework Statement
Given \vec{}r"(t)= 6i-4cos (2t)j+ 9e3tk,
r'\vec{} (0)= 4i +3k and r\vec{}(0)=j+k, find r\vec{}(t).
Homework Equations
The Attempt at a Solution
I will appreciate any ideas how to start this problem. Thank you.