Find Ratio of Segments in Triangle XYZ

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SUMMARY

The problem involves finding the ratio in which point R divides segment PY in triangle XYZ, where point P divides XZ in the ratio 3:1 and point Q is the midpoint of XY. The relevant equation for line segments is given as vector OP = b/(a+b) OA + a/(a+b) OB. The solution requires calculating the vectors RP, RY, RZ, and RQ to establish the desired ratio PR:RY.

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Homework Statement



For triangle XYZ, point P divides XZ in the ratio 3:1 and Q is the midpoint of XY. If R is the point of intersection of PY and QZ, find the ratio into which R divides PY.

Homework Equations



This is the only equation that may pertain to this that I can think of.
For line segment APB, vector OP= b/(a+b) OA + a/(a+b) OB, where O is any point and and b are the ratios.


The Attempt at a Solution



I really need help, this is all i can come up with.

we are looking for PR:RY

RP=1/4 RX + 3/4 RZ
RQ=1/2 RX + 1/2 RY

and RP, RZ, RQ, AND RY are vectors

help please
 
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are there any ideas? Is there something else I can tell you about this problem.
 

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