Find Ratio r of R1/R2 in Two-Resistor Circuit

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In the discussion, the problem involves finding the ratio r of two resistors R1 and R2 connected to a voltage source, with R2 being greater than R1. The relationship between the series and parallel currents is established, leading to the equation Is*(R1+R2) = 10Is*((R1*R2)/(R1+R2)). After some algebraic manipulation, the user initially struggles but later correctly formulates a quadratic equation, ultimately arriving at two potential solutions for r. Given the condition R2 > R1, the valid ratio is determined to be r = 0.127. The discussion highlights the importance of careful algebraic manipulation in solving circuit problems.
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Homework Statement



Two resistors of resistances R1 and R2 , with R2>R1 , are connected to a voltage source with voltage V0 . When the resistors are connected in series, the current is Is . When the resistors are connected in parallel, the current Ip from the source is equal to 10Is

Let r be the ratio R1/R2

Find r

Homework Equations


The Attempt at a Solution



First I found an expression for voltage in each circuit and then equated them to give me

Is*(R1+R2) = 10Is*((R1*R2)/(R1+R2))

Although from here I'm kind of stuck. I'm not sure how to, or even if I am able to manipulate my equation to get R1/R2. Unfortunately it seems my algebra is letting me down in a lot of physics work.
 
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Hi Yaaaldi! :smile:

(Remember, they're also both equal to V0)

There's various ways of solving this, but one is to replace R1 by rR2, to get a quadratic equation in R2. :wink:
 
r^2.R2^2 + rR2^2 + R2^2 = 0

For the quadratic equation in terms of r equation I got a=1, b=1, c=1

if I try to solve this I'll get complex roots..

Have I done something wrong?
 
Hi Yaaaldi! :smile:

(try using the X2 tag just above the Reply box :wink:)
Yaaaldi said:
r^2.R2^2 + rR2^2 + R2^2 = 0

How did you get that? :confused:
 
Nevermind.. somehow managed to forget to write the 10 infront of the rR2^2 on the RHS earlier.

now have a=1 b=-8 and c=1

Solved to get 7.873 and 0.127 for r

and as I know R2>R1

r=0.127

Thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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