Find slope of multivariable function

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SUMMARY

The discussion focuses on finding the steepest points of the multivariable function f(x,y) = 3/(1+x²+y²). The gradient ∇f(x,y) is calculated as ∇f(x,y) = (-6x/(1+x²+y²)²)i + (-6y/(1+x²+y²)²)j. To determine where the slope is maximized, participants suggest maximizing the magnitude of the gradient ||∇f(x,y)|| by differentiating it with respect to x and y, while noting that the square root can be discarded for simplification.

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Homework Statement


A hill is described with the following function:

f(x,y) = 3/(1+x2 +y2)

Where f(x,y) is the height. Find the points where the hill is steepest!

Homework Equations


∇f(x,y) = d/dx(f(x,y))i + d/dy(f(x,y))j

The Attempt at a Solution


d/dx(f(x,y)) = -6x/(1+x2+y2)2
d/dy(f(x,y)) = -6y/(1+x2+y2)2

Know as far as I understand the maximum slope should occur when:

||∇f(x,y)|| has it max. But how should I find that? And am I even going in the right direction?
 
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Yes, that should work. You can write out the expression for ||∇f(x,y)|| and differentiate wrt to x, y, to find out where its extremals are. You can make life a bit easier by noting that you can discard the square root operation, since a positive value is maximised when its square is maximised.
 

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