Find smallest value of k in this equation

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Homework Help Overview

The problem involves finding the smallest value of k in the context of equations relating positive whole numbers m, n, p, and k. The equations given are n^(5/3) = m^(7/2) and nm = p^k, with the goal of determining k based on these relationships.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss expressing n in terms of m and the implications for k in the equation nm = p^k. There are considerations about the conditions under which m and p must be whole numbers, and whether certain expressions must be integers.

Discussion Status

The discussion includes various interpretations of the relationships between m, n, and p, with some participants suggesting that k must be a multiple of 31. Others question whether certain expressions need to be integers and explore different values for k, leading to a range of opinions without a clear consensus.

Contextual Notes

Participants note that m, n, p, and k are constrained to be positive whole numbers greater than 1, which influences their reasoning about the relationships and possible values for k.

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Homework Statement



For these equations m,n,p,k are positive whole numbers greater than 1 .

n^(5/3)=m^(7/2)

nm=p^k

What is the smallest value that k can be?

(A) 6
(B) 11
(C) 31
(D) 41

Homework Equations





The Attempt at a Solution



some hints ?
 
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try to get n in terms of m. Then see what k has to be such that p^k = nm
 


ocohen said:
try to get n in terms of m. Then see what k has to be such that p^k = nm

that leaves me with p^k=m^(31/10)

and i am not told which is greater , p or m
 


you now get m = p^(10k/31) which means p^(10k/31) must be a whole number > 1.
So what does that mean for (10k/31)?
 


ocohen said:
you now get m = p^(10k/31) which means p^(10k/31) must be a whole number > 1.
So what does that mean for (10k/31)?

erm 10k/31>0 ?
 


I would suspect that 10k/31 must be an integer so that p^(10k/31) is also an integer. I don't have any proof for this, but someone else might. As such it means that 10k must be a multiple of 31. Does that make sense?

EDIT: sorry this is incorrect.
 


If we are simply trying to satisfy the equation for the smallest k,
just solve it like this
m^(31/10) = p^k => m^(31/10k) = p
So if k = 6, we just need some m such that its 60th root is a whole number.
So let m = 2^60 or anything like that.
we have that n = m^(21/10) so n is also a whole number.

Does that make sense?
 


well i have another thought on it ,

m=p^(10k/31)

For m is a positive whole number, 10k/31 must be an positive integer and p is known to be a positive whole number.

Therefore ,k must be a multiple of 31 where the smallest is 31 itself. SO the answer is obviously C
 


10k/31 does not need to be a positive integer.
Consider 9^(1/2)
 
  • #10


ocohen said:
10k/31 does not need to be a positive integer.
Consider 9^(1/2)

k is known to be a positive whole number from the question and none of the values of k for
1<k<31 is able to make the indices either a whole number or square roots , cube roots ,...until 31.
 

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