Find Spring Constant k Using Mass & Time Values

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Homework Help Overview

The discussion revolves around finding the spring constant \( k \) using given values for mass and time, specifically in the context of simple harmonic motion. Participants explore the relationship between the period of oscillation and the spring constant through relevant equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula \( T = 2\pi\sqrt{\frac{m}{k}} \) and its rearrangement to solve for \( k \). There is also confusion about calculating the period \( T \) from the average time for multiple vibrations. Questions arise regarding the measurement of time and the correct interpretation of the formulas.

Discussion Status

The conversation is active, with participants clarifying the calculation of the period from the average time for multiple oscillations. Some guidance has been provided regarding the division of total time by the number of vibrations to find the period, but there is no explicit consensus on the overall approach to finding \( k \).

Contextual Notes

Participants are working with specific values, such as a mass of 0.10 kg and a total time of 8.86 seconds for 10 vibrations. There is an emphasis on understanding the definitions and relationships between the variables involved.

HELP_786
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how would i go about finding k with given values for mass and time?

i have seen these equations over and over...but i feel like I am missing something very important that i need..please help me

T=2π√(m/k))

F=-kx
 
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T= 2 \pi \sqrt{\frac{m}{k}}

\Rightarrow T^2=\frac{4 \pi^2 m}{k}

Can you rearrange for k now?
 
Last edited:
o I am sorry i meant how would I go about finding T(period) with given values for time and mass...i forgot to proof read :redface:

those are the formulas i keep seeing everywhere

for example if i had .10kg and 8.86 seconds for the time to find the period would i do this:

T2=(4π2m)/((4π2m)/(8.86))

and then at the end take the square root

?
 
How exactly was the time measured?
 
in seconds

8.86 seconds would be the average time for 10 vibrations in a simple harmonic motion
 
HELP_786 said:
8.86 seconds would be the average time for 10 vibrations in a simple harmonic motion


Period(T) is the time taken for one oscillation/vibration.


10 oscillations/vibrations take 8.86 seconds. How much time would 1 oscillation take?
 
OH! so just divide 8.86s by 10 rite??
 
HELP_786 said:
OH! so just divide 8.86s by 10 rite??

That should yield the time period, yes.
 
i don't believe i didnt realize that! thanku so much! ...im thinking too much lol
 
  • #10
HELP_786 said:
i don't believe i didnt realize that! thanku so much! ...im thinking too much lol

You just need to think about what it is you want to find.
 
  • #11
thanx again! =D
 

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