Find the area under the curve by integration Again

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SUMMARY

The discussion focuses on calculating the area under a piecewise function defined by two segments: Part 1, y = 360(1.029x) for 0 < x < 54, and Part 2, y = 3900(0.98x) + 472 for 54 < x < 144. The specific areas to be calculated are from x=24 to 54 for Part 1 and from x=54 to 120 for Part 2. The user expresses a lack of understanding of integration but is advised to visualize the graph and identify the geometric shapes formed to find the area.

PREREQUISITES
  • Understanding of piecewise functions
  • Basic graphing skills
  • Familiarity with geometric area calculations
  • Knowledge of integration concepts (for advanced understanding)
NEXT STEPS
  • Learn the fundamentals of integration techniques
  • Explore geometric area calculations for irregular shapes
  • Study piecewise function graphing methods
  • Practice finding areas under curves using definite integrals
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Students studying calculus, mathematics educators, and anyone needing to understand area calculations under piecewise functions.

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Homework Statement



This is a piecewise function;
Part 1: y = 360(1.029x) For domain 0 < x < 54
Find the area from x=24 to 54 hours

And Part 2: y = 3900(0.98x) + 472 For domain 54 < x < 144
Find the area from x=54 to 120

Homework Equations


http://upload.wikimedia.org/math/8/1/9/819ac78e8461a8a9c55f3f845e577620.png

The Attempt at a Solution


I still need to learn Integration =/
This is just an extra effort in itself... But I need it done in under half an hour
Please try to help if you have the time =/
 
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In this case, since you need to find area and don't know integration. If you draw your lines and then draw the two x boundaries, it will form a geometric shape, which you should be able to find the area of.

So for y = 360(1.029x), sketch this graph first and then draw the lines x=24 and x=54. What shape does the enclosed region form? Can you find the area now?
 

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