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Density of oak 750kg/m^3

Density of water 1000kg/m^3

There were two parts to the problem, the first is:

Find the location of the center of mass of the plank with respect to the water’s surface. Someone else gave me the equation, so I was able to get this part, but I can't find the equation myself anywhere.

s=side length in meters

w=width in meters

?(oak)=750

?(water)=1000

center mass= w-[(s^2)*w*750/(1000*(s^2))]

Second part (I need help here) is: A very light vegetable oil is poured slowly into the beaker, so that the oil floats on the water without mixing and until the oak plank is a few centimeters below the surface of the oil. If the density of the oil is 640 kg/m3, calculate the new position of the center of mass of the plank with respect to the water’s surface.

For the first part, I got .0075m. As I stated, someone just gave me the equation so I got the answer, but it didn't help me with understanding how to solve the problem. So I am completely lost and if anyone could just point me in the right direction, it would be appreciated.