Find the centripetal acceleration of the moon

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Homework Help Overview

The discussion revolves around calculating the centripetal acceleration of the moon, which orbits the Earth with a specified period and distance. The problem involves understanding the relationship between angular velocity, linear velocity, and the radius of the orbit.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the conversion of angular velocity to linear velocity and the correct interpretation of the radius in the context of the moon's orbit. There are attempts to clarify the formula for centripetal acceleration and the necessary units for velocity.

Discussion Status

Several participants have provided insights into potential misunderstandings regarding the definitions of radius and velocity. There is ongoing exploration of the correct calculations and assumptions, particularly concerning the distance of the moon from the Earth and its implications for the radius used in calculations.

Contextual Notes

There is some confusion regarding whether the given distance of 250,000 miles refers to the radius of the moon's orbit or if it should include the Earth's radius. Participants are also considering the nature of the moon's orbit, which is not perfectly circular.

BrainMan
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Homework Statement


The moon circles the Earth with a period of 27.3 days at a distance of about 250000 mi. Find the centripetal acceleration of the moon.

Homework Equations


ac = v2/r

The Attempt at a Solution


I first found the velocity by converting 2 pi radians per 27.3 days to radians per second.
2 pi / 27.3/ 24/ 60/60 = 2.66 x 10-6 radians per second.
Then I converted miles to meters to find the radius.
250000 x 1609.34 / 2 pi = 631986340.1
Then I plugged these numbers into the above equation to find the acceleration and got 1.12 x 10-20 rad/s. The correct answer is 2.85 x 10-3 rad/s
 
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Seems like you're confusing the angular velocity with the velocity. Also 250000miles is the radius already. No need to divide by 2 pi. Finally, you made some other mistake. I can't tell what it is since you didn't post your calculation. Don't just describe your calculation. Post it.
 
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dauto said:
Seems like you're confusing the angular velocity with the velocity. Also 250000miles is the radius already. No need to divide by 2 pi. Finally, you made some other mistake. I can't tell what it is since you didn't post your calculation. Don't just describe your calculation. Post it.

Sorry (2.66 x 10-6)2/631986340.1 = 1.12 x 10-20
 
In your formula ac = v2/r, v is the velocity in meters/second, not the angular velocity in radians/second.

There is a different formula for the acceleration that uses angular velocity and radius, if you want to do it that way.
 
AlephZero said:
In your formula ac = v2/r, v is the velocity in meters/second, not the angular velocity in radians/second.

There is a different formula for the acceleration that uses angular velocity and radius, if you want to do it that way.
OK I see. Is the 250000 mi the radius or the circumference?
 
BrainMan said:
OK I see. Is the 250000 mi the radius or the circumference?

That's the distance between the moon and the earth. Draw a picture of the orbit, and remember that the Earth barely moves at all.
 
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BrainMan said:
at a distance of about 250000 mi.

dauto said:
250000miles is the radius already.
If it is 250000 mi above the Earth, it should not be the radius. Thou should also include the Radius of the Earth. Am I wrong?
 
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dauto said:
That's the distance between the moon and the earth. Draw a picture of the orbit, and remember that the Earth barely moves at all.

I understand that. How do I find the velocity in m/s?
 
BrainMan said:
I understand that. How do I find the velocity in m/s?

Find the circumference of the orbit (in meters) and divide it by however many seconds are in 27.3 days
 
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  • #10
Nathanael said:
Find the circumference of the orbit (in meters) and divide it by however many seconds are in 27.3 days

OK I got it right! Thanks!
 
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adjacent said:
If it is 250000 mi above the Earth, it should not be the radius. Thou should also include the Radius of the Earth. Am I wrong?

That's negligible specially considering that the moon's orbit really isn't circular. We're going for a ball park calculation here.
 

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