Find the centripetal acceleration of the yoyo

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SUMMARY

The discussion focuses on calculating the centripetal acceleration of a yoyo being swung in a horizontal circle at a 30-degree angle from the vertical. Given the gravitational acceleration (g = 10 m/s²), the tension in the cord is analyzed using trigonometric components. The vertical component of tension balances the weight of the yoyo (mg), while the horizontal component provides the necessary centripetal force. By applying Newton's second law, participants derive the centripetal acceleration from the tension calculated.

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with Newton's second law of motion
  • Basic concepts of circular motion
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about the applications of Newton's laws in circular motion
  • Explore the effects of varying angles on centripetal force
  • Investigate real-world examples of centripetal motion in physics
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding circular motion dynamics.

megha
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hey evr1...i have been trying to do this quest...but somehow can't get it...any help is really appreciated..thnx

a child swings a yoyo of weight mg in a horizontal circle such tht the cord makes an angle of 30 with the vertical. find the centripetal acceleration of the yoyo. (g=10m/s/s)?

it wuld be gr8 if sum1 showd the steps to this problem
 
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Since the yoyo is in constant motion (no acceleration), then the horizontal part of the ropes tension (T*sin(angle)) equals the centripetal force. with the force you can find the acceleration (2 law). You also know that the vertical part of the tension (T*cos(angle)) equals the downward force of gravity (mg). Use that to find the tension, and use the tension to find the centripetal force and acceleration.
 
hey..thnx a lot...u saved ma life..thnx
 

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