Find the centroid of the solid in part (a).

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The discussion focuses on finding the centroid of a solid above a cone and below a sphere, with the volume calculated as 10π. The user is confused about their centroid calculation, particularly the z-coordinate, which they computed as (0,0,21/40), differing from the book's answer. They question the integration setup for zbar, specifically whether they should divide by 4 in their calculations. The user realizes they made a mistake in their integration process, leading to a moment of self-reflection on their errors. Overall, the thread highlights the challenges in accurately applying integration rules in centroid calculations.
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Homework Statement



Find the volume of the solid that lies above the cone
ϕ=pi/3
and below the sphere
ρ=4cosϕ
.

Homework Equations



Find the centroid of the solid in part (a)..

The Attempt at a Solution



For the volume I got 10pi which I am fairly sure is correct. I attempted trying to calculate the centroid and i got a different answer from the book. I have (0,0,21/40)

and I would like to know what did i do incorrect. I calculated ybar and xbar and i got 0.
for zbar, i did the following

∫0→pi/3∫0→2pi∫0→4cosϕ (ρ^3cosϕsinϕdρdθdϕ)the book's answer for the inner integration of rho was ∫0→2pi∫0→pi/3 (cosϕsinϕ(64cos^4(ϕ))dϕdθ

is this correct? isn't supposed to be ∫0→2pi∫0→pi/3 (cosϕsinϕ(64cos^4(ϕ)/4)dϕdθ?

or am I wrong? (I divided by 4, because that's the rule of integration)
 
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Litcyb said:

Homework Statement



Find the volume of the solid that lies above the cone
ϕ=pi/3
and below the sphere
ρ=4cosϕ
.

Homework Equations



Find the centroid of the solid in part (a).


.

The Attempt at a Solution



For the volume I got 10pi which I am fairly sure is correct. I attempted trying to calculate the centroid and i got a different answer from the book. I have (0,0,21/40)

and I would like to know what did i do incorrect. I calculated ybar and xbar and i got 0.
for zbar, i did the following

∫0→pi/3∫0→2pi∫0→4cosϕ (ρ^3cosϕsinϕdρdθdϕ)


the book's answer for the inner integration of rho was ∫0→2pi∫0→pi/3 (cosϕsinϕ(64cos^4(ϕ))dϕdθ

is this correct? isn't supposed to be ∫0→2pi∫0→pi/3 (cosϕsinϕ(64cos^4(ϕ)/4)dϕdθ?

or am I wrong? (I divided by 4, because that's the rule of integration)

You get (4cosϕ)^4/4, right? What's 4^4/4?
 


hahaha!I fell so dumb now. Making very stupid mistakes. thanks for output!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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