Find the coefficient of static friction help?

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To find the coefficient of static friction for an object on an inclined plane, the angle at which it begins to slide is crucial; in this case, it is 35 degrees. The mass of the object is not needed for the calculation, as it will cancel out in the equations. The maximum static friction force is balanced by the component of the object's weight acting down the plane. The correct equation to use is F_s = (μ_s)(N), not the kinetic friction equation. Understanding these principles allows for solving the problem effectively.
rich6490
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Homework Statement


An object rests on an inclined plane. One end of the plane is lifted until the object begins to slide. If the angle at which the object begins to slide is 35 degrees, what is the coefficient of static friction?


Homework Equations


Possibly Fk=("mew"k)N


The Attempt at a Solution


Not even sure where to begin, just knowing the angle can I even solve this problem. Thanks for the help I really appreciate it.

Zach
 
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You need the mass of the object at the least to solve the problem. Otherwise, this is an impossible problem.
 
I talked to a TA at my college, he wouldn't really help me but he said its not that bad of a problem, and to just plug in M for mass, and hope it cancels out when you solve the equations. I'm still a bit confused, so anyones input is greatly appreciated. Thanks a lot.
 
rich6490 said:
I talked to a TA at my college, he wouldn't really help me but he said its not that bad of a problem, and to just plug in M for mass, and hope it cancels out when you solve the equations. I'm still a bit confused, so anyones input is greatly appreciated. Thanks a lot.
Yes, the TA is correct. The object is just on the verge of sliding , but still at rest, when the angle reaches 35 degrees. Therefore, Newton 1 applies, where the max friction force up the plane, F_s =(mu)_s(N) (not F_k or mu_k, which you have incorrectly noted) is balanced by the object's weight component down the plane. Hope that the M cancels when you solve the equation.
 

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