Finding the direction of the force knowing the mu static

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Discussion Overview

The discussion revolves around determining the direction of the applied force needed to move a crate resting on a rough horizontal surface, given a coefficient of static friction of 0.40. Participants explore the mathematical relationships involved in minimizing the applied force while considering various angles of application.

Discussion Character

  • Mathematical reasoning, Technical explanation, Homework-related

Main Points Raised

  • One participant presents the problem and their initial equations relating the applied force, static friction, and normal force, expressing difficulty in proceeding with the solution.
  • Another participant requests a Free Body Diagram (FBD) to better understand the problem and suggests showing the math used to minimize the total force vector.
  • A third participant advises gathering all terms involving the applied force and angle into one side of the equation to facilitate finding a maximum value for a function of the angle.
  • A later reply echoes the previous suggestion, emphasizing the importance of isolating the applied force and maximizing the function related to the angle, recommending plotting it if necessary.

Areas of Agreement / Disagreement

Participants generally agree on the approach of isolating the applied force and maximizing a function of the angle, but there is no consensus on the specific direction of the force or the final solution to the problem.

Contextual Notes

Participants have not resolved the mathematical steps necessary to find the optimal angle for the applied force, and the discussion remains focused on the formulation of the problem rather than reaching a definitive conclusion.

Mafalda
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1. A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of static friction is 0.40. To start the crate moving with the least possible applied force, in what direction should the force be applied?

a. Horizontal

b. 24 degrees below horizontal

c. 22 degrees above the horizontal

d. 24 degrees above the horizontal

e. 66 degrees below the horizontal

Almost 1 hour on this and I really cannot find how to do it! This is the work I’ve done

Fx-fs = 0 <=> Fcosθ = µs . N

Fsenθ + N - W = 0 <=> N = W - Fsenθ

So:
Fcosθ = µs . (W - Fsenθ)

And then I can’t continue! I really need to understand! Thanks!
 
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Mafalda said:
1. A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of static friction is 0.40. To start the crate moving with the least possible applied force, in what direction should the force be applied?

a. Horizontal

b. 24 degrees below horizontal

c. 22 degrees above the horizontal

d. 24 degrees above the horizontal

e. 66 degrees below the horizontal

Almost 1 hour on this and I really cannot find how to do it! This is the work I’ve done

Fx-fs = 0 <=> Fcosθ = µs . N

Fsenθ + N - W = 0 <=> N = W - Fsenθ

So:
Fcosθ = µs . (W - Fsenθ)

And then I can’t continue! I really need to understand! Thanks!
Welcome to the PF. :smile:

I think I know the answer, but I'd like to see your Free Body Diagram (FBD). Could you please Upload a JPEG or PDF of your FBD for this problem, and show how you did the math to minimize the total force vecror needed? Thanks.
 
It will help to gather all the terms containing F and ##\theta## in one side of the equation. Then you ll have the equation in the form

##F\cdot f(\theta)=...## where ##f(\theta)## is a function of theta containing sine and cosine of theta.. In order to minimize F, maximize ##f(\theta)##. It will not be too hard to find the value of theta where f is at maximum.
 
Last edited:
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As @Delta² stated, get F on one side, then if you have F multiplied by a function of Θ equal to some constant, you can maximize the function. You can try plotting it vs Θ if you don't know how to find the maximum.
 
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