Find the critical numbers of the function.

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The function g(y) = (y-1)/(y^2-y+1) has a derivative g'(y) = [y(y-2)]/(y^2-y+1)^2. The denominator, (y^2-y+1)^2, does not yield any critical points since it is always positive. The critical numbers identified are y1 = 0 and y2 = 2, which are correct. A minor note indicates a potential missing minus sign in the derivative. Overall, the critical numbers are accurately determined.
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Homework Statement



g(y)=(y-1)/(y2-y+1)


Homework Equations





The Attempt at a Solution



After I take a derivative, I get
g'(y)=[y(y-2)]/(y2-y+1)2

However,
(y2-y+1)2 does not have any solutions. Am I right that I just throw it away? As an answer, I only leave
y1=0, y2=2

Is that correct?
 
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phillyolly said:

Homework Statement



g(y)=(y-1)/(y2-y+1)


Homework Equations





The Attempt at a Solution



After I take a derivative, I get
g'(y)=[y(y-2)]/(y2-y+1)2

However,
(y2-y+1)2 does not have any solutions. Am I right that I just throw it away? As an answer, I only leave
y1=0, y2=2

Is that correct?

I wouldn't say "throw it away". I would just observe that the denominator is always positive. And I think you have a minus sign missing but your critical numbers are correct.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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