Find the derivative of the function

[bobsmith76]

Homework Statement

The Attempt at a Solution

I don't understand how in the final step they got the numerator. Where's the 45 come from? what happened to 2t+1?, or in the denominator they got (2t+1) raised to the 10th power.

 

[Dick]

h'(x)=2. Why do you say '2 or 1'?? And (2t+1)*1-2*(t-2)=5. Multiply it out. Finally $({\frac{t-2}{2t+1})}^8=\frac{(t-2)^8}{(2t+1)^8}$. Does that help?

 

[bobsmith76]

You read my post before I edited it. I'm still having trouble getting 45, and the 10th power in the denominator.

 

[Dick]

You read my post before I edited it. I'm still having trouble getting 45, and the 10th power in the denominator.

9*5=45. And (2t+1)^8*(2t+1)^2=(2t+1)^10.

 

[bobsmith76]

Ok, I figured out the numerator, I can get 45 now. But I still can't get the 10th power in the denominator.

 

[SithsNGiggles]

I'm still having trouble getting 45, and the 10th power in the denominator.

9 ((t - 2)/(2t + 1))^8 ((2t + 1)(1) - (2)(t -2))/(2t + 1)^2)

9 ((t - 2)/(2t + 1))^8 (2t + 1 - 2t + 4)/(2t + 1)^2

Simplify from here.

Also, ((t - 2)/(2t + 1))^8 is the same as (t - 2)^8/(2t + 1)^8

 

[bobsmith76]

Thanks, I got it now.