Find the derivative of:y= (ax + sqrt of x^2 +b^2)^-2

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SUMMARY

The derivative of the function y = (ax + √(x² + b²))⁻² is confirmed to be -2(ax + √(x² + b²))⁻³ * (a + 2/√(x² + b²)) * 2x. Participants in the discussion agree on this result, with slight variations in their expressions. The derivative involves applying the chain rule and product rule effectively, showcasing the complexity of differentiating composite functions.

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ace123
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The question is Find the derivative of:
y= (ax + sqrt of x^2 + b^2)^-2

I got this

-2(ax + sqrt of x^2 + b^2)^-3 *(a+ 2/ sqrt of x^2 + b^2) *2x

but i dno if this is right, can someone help me.
 
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Yea I got the same thing minus 2/ sqrt of x^2 + b^2

It should be 1/(2*biggiantmess^1/2)

or u^1/2 = 1/(2*u^1/2)
 

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