Find The Derivative of y = sinh^-1 (1/x)

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SUMMARY

The derivative of the function y = sinh-1(1/x) can be found using implicit differentiation. Starting with the equation sinh(y) = 1/x, the differentiation process leads to the formula y' = -1/(cosh(y) * x2). To complete the solution, cosh(y) must be expressed in terms of x using hyperbolic identities. This approach simplifies the differentiation process and provides a clear path to the solution.

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  • Understanding of hyperbolic functions, specifically sinh and cosh.
  • Knowledge of implicit differentiation techniques.
  • Familiarity with calculus concepts, particularly derivatives.
  • Ability to manipulate algebraic expressions involving trigonometric identities.
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  • Study hyperbolic function identities and their derivatives.
  • Learn more about implicit differentiation methods in calculus.
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Homework Statement



Differentiate

y = sinh^-1 (1/x)

Homework Equations





The Attempt at a Solution




y' = 1 / sqrt 1 + (1/x)^2 x -1/x^2


Really confused with this.

Is there a different method to this like;


y = sinh^-1 (1/x)

sinh y = 1/x


Thanks
 
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You're on the right track with implicit differentiation. Keep going down this path:
sinh(y)=\frac{1}{x}
cosh(y) dy = -\frac{1}{x^2}dx
cosh(y)\frac{dy}{dx} = -\frac{1}{x^2}
y'=-\frac{1}{cosh(y) x^2}
Now express cosh(y) in terms of x using identities and you're done.
 

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