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LNy = 2xLN(sinx) + (1 over sinx)(cosx)(2x)

Answer

y' = (sinx)^{2x}[2cosx over sinx + 2xcotx]

and

y = (cosx)^{cosx}

i did it the same way as above

Answer i got was

y' = (cosx)^{cosx}[ (-sinx)(cosx) + sinx]

am i anywhere right?

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# Homework Help: Find the derivative using Logaritmic Differentiation

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