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Find the derivitive of the function? Help

  1. May 30, 2012 #1
    Find the derivitive of the function? Help:)

    1. The problem statement, all variables and given/known data
    g(x)=√x^2-2x+1



    2. Relevant equations



    3. The attempt at a solution
    I rewrote the problem as g(x)=(x^2-2x+1)^1/2
    Then..
    1/2(x^2-2x+1)^-1/2(2x-2)(2)
    But I got it wrong at that step whenever I wrote the "2"
    Can you help?
     
  2. jcsd
  3. May 30, 2012 #2

    Mark44

    Staff: Mentor

    Re: Find the derivitive of the function? Help:)

    You don't need that final 2. What you have is u1/2, where u = x2 - 2x + 1.
    d/dx(u1/2) = (1/2)u-1/2 * du/dx
     
  4. May 30, 2012 #3
    Re: Find the derivitive of the function? Help:)

    Ok, I understand.. But for some reason I was wanting to write the derivitave of 2x, which is 2 right??
     
  5. May 30, 2012 #4

    Mark44

    Staff: Mentor

    Re: Find the derivitive of the function? Help:)

    du/dx = 2x - 2
     
  6. May 30, 2012 #5
    Re: Find the derivitive of the function? Help:)

    Ohhhh ohk I knew that..Thanks Alot :D
    Could you please take a look at my other post?
     
  7. May 30, 2012 #6

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Re: Find the derivitive of the function? Help:)

    Actually, [itex]y= (x^2- 2x+ 1)^{1/2}= ((x- 1)^2)^{1/2}= |x- 1|[/itex]
    That has derivative -1 if x< 1, 1 if x> 1 and is not differentiable at x= 1.

    That is the same as [itex]y'= (1/2)(x^2- x+ 1)^{-1/2}(2x- 2)= (x-1)/|x- 1|[/itex].
     
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