How in the world did you get this? Surely not by taking the square root of both sides!UWMpanther said:Homework Statement
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius r.
Homework Equations
(x-a)^2 + (y-b)^2 = r^2
max area = 2x(2y)
= 4xy
The Attempt at a Solution
(x-a)^2 + (y-b)^2 = r^2
= y=r-(x-a)+b
No, it not at all set up properly!I then plug this into the max area
= 4x(r-(x-a)+b)
I know I need to differentiate, but I'm not sure how to go about this. I know I need to use the product rule, if its setup properly.
The formula for finding the dimensions of a rectangle is length x width. This means multiplying the length of the rectangle by its width.
To determine the length and width of a rectangle if you know its perimeter and area, you can use the formulas P = 2(l + w) and A = lw, where P is the perimeter, A is the area, l is the length, and w is the width. You can rearrange the equation for perimeter to solve for one variable, then plug that value into the area equation to solve for the other variable.
Yes, a square is a type of rectangle where the length and width are the same number. However, in a regular rectangle, the length and width will typically be different numbers.
A rectangle has two dimensions: length and width. This means that it is a 2-dimensional shape.
No, the Pythagorean theorem is used to find the length of the hypotenuse in a right triangle. It cannot be applied to a rectangle, which is a different shape.