Find the Electric Field at a midway point

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field at a midpoint between two point charges: +30.0 x 10^-9 C and +60.0 x 10^-9 C, separated by 30 cm. The initial calculations using the formula E = k(Q/r^2) yielded 3000 N/C and 6000 N/C for each charge, respectively, leading to an incorrect total of 9000 N/C. The correct approach involves recognizing that the electric fields from both charges should be considered in terms of their directions, resulting in a net electric field of 3000 N/C at the midpoint after proper vector addition.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with the concept of superposition in physics
  • Basic knowledge of vector addition
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Study Coulomb's Law and its applications in electrostatics
  • Learn about vector addition and how it applies to electric fields
  • Explore the concept of electric field lines and their directionality
  • Practice problems involving multiple point charges and their electric fields
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electric fields and charge interactions.

1126
Messages
7
Reaction score
0
The problem is:
Find the electric field at a point midway between two charges of +30.0 x 10^-9C and +60.0 x 10^-9 C separated by a distance of 30 cm.


I used E=k (Q/r^2)
My attempt is:

E=(9x10^9)(30.0 x 10^-9C)/(.3m^2)
E=3000 N/C

E=(9x10^9)(60.0 x 10^-9 C)/(.3m^2)
E=6000 N/C

added they are 9000 N/C. I am fairly certain this is incorrect, but I do not understand the material. I really have no idea why or how to go about finding the correct answer. Please help!
 
Physics news on Phys.org
I think you might want to try subtracting them like 6000-3000=3000.
I think that electric fields go away from positive charges
 
I still don't really understand. Is .3m really the right radius? It's the distance between the charges, but I'm not sure if it's the right radius to use. Any suggestions? :/
 
Always draw a diagram. If the two charges are separated by 30 cm, how far is the mid point from each charge? Pay attention to the directions of the fields that each charge produces at the given location.

attachment.php?attachmentid=44425&stc=1&d=1330304042.gif
 

Attachments

  • Fig1.gif
    Fig1.gif
    1.1 KB · Views: 1,668
Thank you so so so much! that was so helpful! I think I solved it correctly now. :) thanks so much!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
997
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K