Find the Electric field at point p

Click For Summary
The discussion revolves around calculating the electric field at point P due to charges q3 and q4, which cancel each other out. The user struggles with finding the radius needed for the electric field formula, E=(kq)/r^2, as it is not provided in the problem statement. Participants clarify that the positions of the charges relative to point P are sufficient to determine the electric field, even without a numerical value for the distance. It is suggested to express the radius as a variable (d) in the final answer if no specific value is given. Understanding the relationship between the charges and their distances is crucial for solving the problem effectively.
NotInMrPutmansClass
Messages
5
Reaction score
0
Homework Statement
Calculate the net electric field at point P from the diagram below
Relevant Equations
E=(kq)/r^2

Where k is plank's constant 9×10^9
R= distance or radius
Since q3=q4 and they are opposite to each others they cancel out
But as soon as I try to find the electric field of one of the charges, I need the radius which is not given.

By isolating the electric field for radius

E=(kq)/r^2
I now have two unknowns
 

Attachments

  • 20221115_073652.jpg
    20221115_073652.jpg
    17.2 KB · Views: 122
Physics news on Phys.org
Can you post the full problem statement as it was given? (k is Coulomb's constant, not Planck's constant.)
 
NotInMrPutmansClass said:
Homework Statement:: Calculate the net electric field at point P from the diagram below
Relevant Equations:: E=(kq)/r^2

Where k is plank's constant 9×10^9
R= distance or radius

I need the radius which is not given.
What radius is this? You are given the positions of all charges relative to the point of interest P which is all you need to find the electric field at P. If you are not given a numerical value for distance ##d##, then leave it as ##d## in your answer.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
876
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
994
Replies
23
Views
3K