Find the electric field at the origin

[Rijad Hadzic]

Homework Statement

Given two charged particles:

1) 5x10^-9 C, (-.03 m, 0 m)
2) -20x10^-9 C (.04 m, .02 m)

find the electric field at the origin.

Homework Equations

F = (kQq)/r^2
E = (kQ)/r^2

The Attempt at a Solution

So I know since 1)'s charge is plus, its field vector is

$( (8.99x10^{-9}) (Q) ) / (.03)^2$ i hat, meaning its going to the right

I use arctan to find the angle between the origin and 2), it is 26.57 deg, and pathagorean theorem to find the distance r to be .045m

since 2) is - charged, its electric field is going away from the origin at 26.57 degrees.

$( (8.99x10^{-9}) (Q) ) / (.045)^2$

Now I can break it down into components, but how am I suppose to find Q, the charge of the origin?

If they gave me a value for the electric force between the origin and one of the particles I can find Q, but with this information I don't see any way I can find it?

 

[TSny]

There is no charge at the origin. In the formula E = kQ/r², Q is the charge that is producing the electric field. Each of the two charges that are given in the problem is producing electric field at the origin.

 

[Rijad Hadzic]

There is no charge at the origin. In the formula E = kQ/r², Q is the charge that is producing the electric field. Each of the two charges that are given in the problem is producing electric field at the origin.

Thank you sir. I was wasting my time on this question for 2 hours already.. now my answer matches my books answer. TY.

 

[TSny]

OK, good work.